regex - Substitute the n-th occurrence of a word in vim -

I looked at other questions working with finding a n / a phenomenon of a word / pattern, but I do not know That's how you would actually replace the N-th event of a pattern in vim.

 : s /.* \ (word \). * \ (word \). * \ (word \). * /. * All such events are a clear way of coding coding. \ 1 * \ 2. * New Word. * / G  

Is there a better way to do this?

You can do it a bit more easily by using many searches : s / In the pattern / repl / command, the empty pattern means to change the most recent search result.

 : / word // word // word / s / / code / s / word / newword /  

by doing this again, or even <<10p>

Alternatively, if I was interacting with this, then I would do something like this:

  3 / word: s // newWord / r  

This will receive the third instance of the word starting on the cursor and then the replacement.